The period of sin (x+8x+27x+ ……….. +n3x) is

sin⁡x+8x+27x+⋯+n3x=sin⁡n2(n+1)24x Period =2πn2(n+1)2/4⇒8πn2(n+1)2

The period of sin (x+8x+27x+ ……….. +n3x) is

sin⁡x+8x+27x+⋯+n3x=sin⁡n2(n+1)24x Period =2πn2(n+1)2/4⇒8πn2(n+1)2

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The period of sin (x+8x+27x+ ……….. +n³x) is

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$8 π / n^{2} (n + 1)^{2}$

$4 π / n (n + 1)$

$8 π / n (n + 1)$

$4 π / n^{2} (n + 1)^{2}$

answer is A.

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$\sin (x + 8 x + 27 x + \dots + n^{3} x) = \sin [\frac{n^{2} {(n + 1)}^{2}}{4} x] Period = \frac{2 π}{n^{2} (n + 1)^{2} / 4} \Rightarrow \frac{8 π}{n^{2} (n + 1)^{2}}$

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The period of sin (x+8x+27x+ ……….. +n³x) is