Q.

The period of tan (x + 8x + 27x + …+n3x) is

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a

4πn(n+1)

b

8πn2(n+1)2

c

4πn2(n+1)2

d

2πn2(n+1)2

answer is B.

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Detailed Solution

f(x)= tan (x+8x+27x+....+n3x)

fx=tan13+23+33+....+n3x f(x)=tann2n+124x period=πn2n+124=4πn2n+12

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