Q.

The period of sin2πxa+3cos2πxb when a=12,b=9 is

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a

36

b

54

c

108

d

18

answer is B.

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Detailed Solution

fx=sin2πxa+3cos2πxb  substitute a=12,b=9 f(x)=sinπ6x+3cos2π9x period of sinπ6x=2ππ6=12 period of cos2π9x=2π2π9=9 Period of fx=sin2πxa+3cos2πxb  is LCM of 12,9=36 period =36 

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