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Q.

The perpendicular distance between the force and the turning point, if a force of $20 N$ produces a moment of force of $10 Nm$ is

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a

0.8 m

b

0.7 m

c

0.6 m

d

0.5 m

answer is D.

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Detailed Solution

Given:
Moment of force

τ = 10 Nm

Force = 20 N

To find:
Perpendicular distance between the force and the turning point
We know, the turning effect produced by a force on a rigid body about a point is called the moment of force or torque. It is measured by the product of force and the perpendicular distance of the fulcrum from the line of action of force.
Moment of a force (turning) = Force x perpendicular distance of the pivot from the force.
Therefore

τ = F \times d sin 90 °

\Rightarrow 10 Nm = 20 N \times d (1)

\Rightarrow \frac{10}{20} = d

∴ d = 0.5 m

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The perpendicular distance between the force and the turning point, if a force of 20 N produces a moment of force of 10 Nm is