The PH of NaOH solution is 12. Then the PH of H2SO4 solution having same molar concentration of NaOH solution is

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The $P^{H}$ of $N a O H$ solution is 12. Then the $P^{H}$ of $H_{2} S O_{4}$ solution having same molar concentration of $N a O H$ solution is

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3.398

1.7

answer is C.

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Detailed Solution

$[N a O H] = 10^{- 2} M$

$[H_{2} S O_{4}] = 10^{- 2} M$

$[H^{+}] = 2 \times 10^{- 2} M$

$P^{H} = - \log (2 \times 10^{- 2})$

$= 2 - \log 2$

$= 2 - 0.301$

$= 1.699 \approx 1.7$

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