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Q.

The pH at which Mg(OH)2 begins to precipitate, if the concentration of Mg+2 is 0.1M (Ksp of Mg(OH)2 = 1.0 × 10–11)

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a

9

b

3

c

5

d

12

answer is C.

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Detailed Solution

For precipitation to occur, the ionic product must exceed the solubility product.

KIP = Ksp

⇒ [Mg+2] [OH-]2 = 10-11

⇒ [OH-]2 = 10-10

⇒ [OH-] = 10-5

POH = 5

\large \therefore P^H=9

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