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Q.

The pH of 40 ml of a 0.02 M HCl will not be changed by adding

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a

2 ml of 1M NaOH

b

1 ml of 1M HCl

c

20 ml of 0.1 M NaCl

d

36 ml of same concentrated HCl solution

answer is D.

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Detailed Solution

 Initial pH of 40 ml of a 0.02 M HCl: pH = -log[H+] = -log[0.02] = 1.70

pH of solution after adding 36 ml of same concentrated HCl solution = -log[0.02] = 1.70

Since the pH doesn’t change but only the volume which is changed.

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