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Q.

The pH of a buffer solution containing 0.05 M Na3PO4 and 0.1 M Na2HPO4 is  11.7 .The ionization constant HPO42− is

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a

1.0×10−10 M

b

1.0×10−11 M

c

1×10−9 M

d

1.0×10−12 M

answer is D.

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Detailed Solution

pH=pKa+log⁡[salt][acid]=pKa+log⁡0.05 M0.10 M 

Hence 11.7=pKa−0.30. 

This give pKa=12.0

Hence, Ka=1.0×10−12 M

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