Q.

The pH of a buffer solution made by mixing 25 ml of 0.02 M NH4OH and 25 ml of 0.2 M NH4Cl at 250C is : (pKb of NH4OH = 4.8)

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a

8.2

b

4.8

c

5.8

d

3.8

answer is B.

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Detailed Solution

Given data: It is given to find out pH of a buffer solution made by mixing 25 ml of 0.02 M NH4OH and 25 ml of 0.2 M NH4Cl at 250C.

Concept used: pOH = pKb+log[salt][base], pH + pOH =14

Explaination: pOH = pKb+log[salt][base]

= 4.8 + log[0.2][0.02]

= 4.8 + 1 = 5.8

pH + pOH =14

pH + 5.8 = 14

pH = 14 – 5.8 = 8.2

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