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Q.

The pH of a sample of KOH solution is 12.3979. The weight of solid KOH of 70% pure required to prepare 2.5 lit of this solution is

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a

6 g

b

5 g

c

8 g

d

3.5 g

answer is B.

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Detailed Solution

POH = 14 - 12.3979 ~ 1.6

[OH-] = 2.5 x10-2

Let us consider, w g of KOH is required

70×w100×56×2.5=2.5×10-2

⇒ w = 5 

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