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Q.

The pH of a sample of KOH solution is 12.3979. The weight of solid KOH of 70% pure required to prepare 2.5 lit of this solution is

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a

6 g

b

5 g

c

8 g

d

3.5 g

answer is B.

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Detailed Solution

P^OH = 14 - 12.3979 ~ 1.6

[OH^-] = 2.5 x10^-2

Let us consider, w g of KOH is required

$\frac{70 \times w}{100 \times 56 \times 2.5} = 2.5 \times 10^{- 2}$

⇒ w = 5

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