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The pH of a solution is 12. Number of H⁺ ions present in 1 ml of this solution at 25⁰C is

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10^-12

6.02 x 10⁸

10^-2

6.02 x10²⁰

answer is C.

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Detailed Solution

[H⁺] = 10^-12

n_H⁺present in 1 ml of solution = 10^-12 x 1 x 10^-3

= 10^-15

Number of H⁺ ions present in 1 ml of solution

= 10^-15 x 6.023 x 10²³

= 6.023 x 10⁸

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