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The pH of a weak mono basic acid is 5. The degree of ionization of acid in 0.1 M solution is

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$10^{- 3}$

$1 O^{- 1}$

$10^{- 2}$

$10^{- 4}$

answer is A.

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Detailed Solution

$HA ⇌ H^{+} + A^{-}$

pH = 5

pH + pOH = 14

$∴ P^{OH} = 14 - 5 = 9$

$[H^{+}] = 10^{- 5}$

$C = 10^{- 5}$

$C = 10^{- 1}$

$[H^{+}] = C α$

$α = \frac{[H^{+}]}{C} = \frac{10^{- 5}}{10^{- 1}} = 10^{- 4}$

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