The pH of pure water at $50° \mathrm{C}$ is 6.63. What is the value of ${\mathrm{K}}_{\mathrm{\omega }}$ at $50° \mathrm{C}$?

Given,

pH of pure water =6.63  (at $50° \mathrm{C}$)

The value of ${\mathrm{K}}_{\mathrm{\omega }}$ at this temperature,

$$\begin{gathered} {\mathrm{k}}_{\mathrm{\omega }}={10}^{-6.63}\times {10}^{-6.63} \\ {\mathrm{k}}_{\mathrm{\omega }}=5.5\times {10}^{-14} \end{gathered}$$