The pH of the solution containing 50ml each of 0.10M sodium acetate and 0.01M acetic acid is [ Given Pka of CH3COOH=4.57 ]

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The pH of the solution containing 50ml each of 0.10M sodium acetate and 0.01M acetic acid is [ Given Pk_a of ${CH}_{3} COOH = 4.57$ ]

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2.57

3.57

5.57

4.57

answer is B.

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Detailed Solution

According to henderson equation

$\begin{array}{l} P^{H} = p^{ka} + \log \frac{[salt]}{[Acid]} \\ = 4.57 + \log \frac{0.10}{0.01} \\ = 4.57 + \log 10 = 4.57 + 1 = 5.57 \end{array}$

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