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The phase difference between the displacement and acceleration of a particle executing simple harmonic motion is

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zero

$π / 2$

$π$

$2 π$

answer is C.

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Detailed Solution

$Since y = A \sin ϕ and a = - ω^{2} A \sin ϕ$

$and - \sin ϕ = \sin (π + ϕ)$

So, acceleration is ahead of displacement by a phase $π$

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