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Q.

The phase difference between two SHM y1 = 10 sin (10πt + π3) and y2 = 12 sin (8πt+π4) at t = 0.5 s is

 

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a

13π12

b

11π12

c

17π12

d

π

answer is B.

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Detailed Solution

Phase for 1st SHM:  = 10πt+π3

Phase for 2nd SHM:  2 = 8πt+π4

Phase difference:  = 1-2 = 2πt + π12

Put t = 0.5 s

 = 2π(0.5)+π12 = 13π12

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