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The phase of a particle in SHM at time $t$ is $π / 6$ . The following inference is drawn from this:

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The particle is at $x = a / 2$ and moving in $- X -$ direction

The particle is at $x = a / 2$ and moving in $+ X -$ direction

The particle is at $x = - a / 2$ and moving in $+ X -$ direction

The particle is at $x = - a / 2$ and moving in $- X -$ direction

answer is A.

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Detailed Solution

$t = \frac{T}{4} (\frac{π}{2} A n g l e)$

$\frac{π}{6}$ phase will develop when particle move from mean position towards amplitude position. It means particle move in $+ x$ direction

$x = a \sin ω t$

$x = a \sin θ$

$x = a \sin \frac{π}{6} = a \sin 30 ° = \frac{a}{2}$

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