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Q.

The pitch of the screw gauge is 1mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72nd division on circular scale coincides with the reference line. The radius of the wire is

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a

1.80 mm

b

0.90 mm 

c

1.64 mm

d

0.82 mm

answer is B.

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Detailed Solution

Least count = 1mm 100 =0.01mm   zero error =+8×LC=+0.08mm  
True reading Diameter =1mm+72×LC− Zero error   
=1mm+72×0.01mm−0.08mm=1.72mm−0.08mm=1.64mm  
∴ radius = 1.64 2 =0.82mm    
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