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The pKa of HCN is 9.30. The pH of a solution prepared by mixing 2.5 moles of KCN and 2.5 moles of HCN in water and making up to a volume of 500 mL is

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10.30

8.30

9.30

7.30

answer is A.

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Detailed Solution

${PK}_{a} = 9.3; PH = {pK}_{a} = 9.3$

Because ${PK}_{a} = - PH + \log_{10}^{\frac{[salt]}{[acid]}}$

[salt] = 2.5[KCN]

[Acid] = 2.5[HCN]

$∴ P^{K_{a}} = P^{H} = 9.3$

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