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The plane which can be formed with the vectors $\bar{a} = 3 \bar{i} - 4 \bar{j} + 2 \bar{k}$ , $\bar{b} = 2 \bar{i} - \bar{j} - 6 \bar{k}, \bar{c} = 5 \bar{i} - 5 \bar{j} - 4 \bar{k} is.$

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Hyperbola

Circle

Triangle

Quadrilateral

answer is B.

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Detailed Solution

$\hat{a} + \hat{b} - \hat{c} = \bar{0} (triangle law)$

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