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The plates in a parallel plates capacitor are separated by a distance d with air as the medium between the plates. In order to increase the capacity by 66% a dielectric slab of thickness 3d/5 is introduced between the plates. What is the dielectric constant of the dielectric slab?

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1.5

1.66

answer is B.

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Detailed Solution

$Capacity in air C = \frac{ε_{0} A}{d}$

$C^{'} = \frac{ε_{0} A}{(d - t) + \frac{t}{k}} t = \frac{3 d}{5}$

$Given C^{'} = \frac{166}{100} C$

$\frac{100}{166} = \frac{(d - t) + \frac{t}{K}}{d}$

On putting values

K = 3

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