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Q.

The plates of a parallel plate capacitor are charged up to 100 volt. A 2 mm thick plate is inserted between the plates, then to maintain the same potential difference, the distance between the capacitor plates is increased by 1.6 mm. The dielectric constant of the plate is

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a

5

b

1.25

c

4

d

2.5

answer is A.

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Detailed Solution

C0=ϵ0Ad C=ϵ0Ad+x−t+tk

If C=C0

x=t1−1K

On solving we get K=5

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