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Q.

The plates of a parallel plate capacitor are charged up to 100 volt. A 2 mm thick plate is inserted between the plates, then to maintain the same potential difference, the distance between the capacitor plate is increased by 1.6 mm. The dielectric constant of the plate is

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a

5

b

1.25

c

4

d

2.5

answer is A.

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Detailed Solution

When dielectric slab is introduced 
V=E0d−t1−1K
Hence to maintain the same potential difference, the plates should be increased by
t1−1K=d′
or    21−1K=1⋅6  or  K=5

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