The plates of a parallel plate capacitor with no dielectric are connected to a voltage source. Now a dielectric of dielectric constant K is inserted to fill the whole space between the plates with voltage source remaining connected to the capacitor. Select the incorrect statement(s).

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The energy stored in the capacitor will become K - times the initial energy

The electric field inside the capacitor will decrease K - times the initial field

The force of attraction between the plates will become $K^{2} -$ times the initial force

The charge on the capacitor will become K - times the initial charge

answer is B.

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Detailed Solution

A) $U = \frac{1}{2} C V^{2}$
As source between the plates is connected, so potential difference remains constant. But capacitance C becomes KC hence energy stored is increased by factor K.
B) Electric field $\frac{V}{d}$ is not changed
C) Charge on each plate is increased by factor K hence force between them increases by a factor of $K^{2}$ .
D) Since $Q = C V$
Hence charge becomes KQ as C becomes KC and V remains unchanged.
Hence, (A), (C) and (D) are correct