The plates of an isolated capacitor have equal and opposite charge of magnitude $Q_{0}$ . A positive insulator plate having same area as capacitor plates, and positive charge $Q_{0}$ is brought just outside the positive plate and kept parallel to it. Which of the following options is/are correct?

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A net attractive force acts on the insulator plate due to the capacitor

The outer surfaces of the capacitor plates have equal and opposite charges

The electric field between the capacitor plates increases

The net interaction force between the insulator plate and the negative plate of the capacitor is zero

answer is A, B.

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Detailed Solution

E l e c t r i c f i e l d a t a n y p o i n t b e t w e e n t h e p l a t e s i s t h e v e c t o r s u m o f f i e l d p r o d u c e d b y t h e c h a r g e o f t h e c a p a c i t o r p l a t e s (b e f o r e t h e i n s u l a t o r p l a t e w a s p l a c e d) a n d t h e f i e l d p r o d u c e d b y t h e i n s u l a t o r p l a t e . T h e f i e l d p r o d u c e d b y t h e i n s u l a t o r p l a t e i n d u c e s - \frac{Q_{0}}{2} a n d + \frac{Q_{0}}{2} c h a r g e s o n t h e o u t e r s u r f a c e s o f t h e o u t e r p l a t e s o f t h e c a p a c i t o r .

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