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Q.

The plot of logkf  versus 1Tfor a reversible reaction AgPgis shown.
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Pre-exponential factors for the forward and backward reactions are 1015s1  and 1011s1,  respectively. If the value of   for the reaction at 500 K is 6, the value of logKb  at 250 K is ___.
[K = equilibrium constant of the reaction
kf  = rate constant of forward reaction
kb = rate constant of backward reaction]
 

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answer is 5.

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Detailed Solution

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K=KfKb At T=500KKf=109K=106Kb=KfK=103Kb=1011eEa/RT
At 500K, logKb=11log10eEaRT
3=11log10eEaR500
log10eEaR500=8

At 250 k  logKb=11log10eEaR250
=1182 =5 logKb=5

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