The point of inflection of $y=x^3-5x^2+$ $3x – 5$ is

Since $y$ is twice differentiable function so for inflection points $y^{\text{'}\text{'}}\left(x\right)=0,y^{\text{'}\text{'}\text{'}}\left(x\right)\ne 0$

$y^{\text{'}}\left(x\right)=3x^2-10x+3$

$y^{\text{'}\text{'}}=6x-10. \text{ So, }{y}^{\text{'}\text{'}}\left(x\right)=0\text{ if }x=\frac{5}{4}$

$y^{\text{'}\text{'}\text{'}}\left(x\right)=6\ne 0. \text{ So, }x=\frac{5}{4}$ is a point of inflection.