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The point P on the line passing through $A (3 i + 2 j - 3 k)$ and parallel to the vectors $2 i - 2 j + k$ such that AP = 6 is

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$7 i - 2 j - k$

$5 i - 2 k$

$i + 4 j - 4 k$

$i - 4 j + 4 k$

answer is A.

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Detailed Solution

$AP = t (2 i - 2 j + k) 6 = |t| \sqrt{4 + 4 + 1} \Rightarrow t = \pm 2 OP = 3 i + 2 j - 3 k \pm 2 (2 i - 2 j + k)$

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