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The point P(x, y) is equidistant from the points Q(c + d, d – c) and R(c – d, c + d) then

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cx = dy

cx + dy = 0

dx = cy

dx + cy = 0

answer is C.

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Detailed Solution

$P Q = P R \Rightarrow P i s m i d p o i n t o f Q R \Rightarrow (x, y) = (c, d) \Rightarrow c = x, d = y$

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