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The point to which the origin has to be shifted to eliminate x and y terms in the equation $3 {(x - 2)}^{2} + 5 {(y + 3)}^{2} = 6$

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An Intiative by Sri Chaitanya

(2, -3)

(-2, -3)

(2, 3)

(-2, 3)

answer is A.

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Detailed Solution

$3 [x^{2} + 4 - k x] + 5 [y^{2} + 9 + 6 y] = 6$
$3 x^{2} + 5 y^{2} - 12 x + 30 y + 12 + 45 - 6 = 0$
$= (\frac{- g}{a}, \frac{- f}{b}) = (\frac{6}{3}, \frac{- 15}{5}) = (2, 3)$

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