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The points lies on opposite side of the line $3 x - 4 y + 5 = 0$

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$(1, 1) (2, 1)$

none

$(- 1, 1) (- 2, 0)$

$(2, 0) (1, - 1)$

answer is D.

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Detailed Solution

$3 x - 4 y + 5 = 0$

A) $L_{11} = L_{(- 1, 1)} = 3 (- 1) - 4 (+ 1) + 5 = - 2$

$L_{22} = L_{(- 2, 0)} = 3 (- 2) - 4 (0) + 5 = - 1$

Same sign, same side.

B) $L_{11} = L_{(1, 1)} = 3 (1) - 4 (1) + 5 = 4$

$L_{22} = L (2, 1) = 3 (2) - 4 (1) + 5 = 7$

Same side.

C) $L_{(2, 0)} = 3 (2) - 4 (0) + 5 = + 11$

$L_{(1, - 1)} = 3 (1) - 4 (- 1) + 5 = 12$

Same sign, same side.

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