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The Poisson ratio for the material of a wire is 0.4. When a force is applied on the wire, longitudinal strain is (1/100). The percentage change in the radius of the wire is

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0.1

0.8

0.4

0.2

answer is C.

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Detailed Solution

$σ = - \frac{∆ r / r}{∆ l / l}; \frac{∆ l}{l} = - \frac{1}{100}; σ = 0.4$

$0.4 x \frac{1}{100} = - \frac{∆ r}{r}$
% change $= \frac{0.4}{100} x 100 = 0.4 %$

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