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Q.

The polynomials ax2+3x2−3 and 2x3−5x+a when divided by (x−4) leaves remainders R1 and R2 respectively then value of a if 2R1−R2=0, is

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a

−18127

b

18127

c

17127

d

−17127

answer is A.

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a=−18127

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