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The population of a city increases each year by $4 %$ of what it had been at the beginning of each year. If the population in 1999 had been 6760000, find the population of the city in 2001.

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7311616

6281616

7312626

7362716

answer is A.

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Detailed Solution

Given,
Population of a city in 1999,
P=6760000 Increase growth rate of population,
R=4% Number of years, n=2
Population of a city in 2001

= P 1 + R 100 n

⇒ 6760000 1 + 4100 2 ⇒ 6760000 1 + 125 2 ⇒ 6760000 × 2625 × 2625 ⇒ 7311616

Hence, the population of a city in 2001 will be 7311616.
Hence, the correct option is 1.

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