Q.

The population of a particular area of a city is 5000. It increases by 10% in 1styear. It decreases by 20% in the 2nd year because of some reason. In the 3rd year, the population increases by 30%. What will be the population of area at the end of 3 years?


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a

 5120

b

 5300

c

 5720

d

 5620  

answer is C.

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Detailed Solution

It is given,
Population of a city at the starting of first year =5000.
It increases by 10% in 1st year,
Population at the end of 1st year = Population at the starting of 2nd year,
5000+10% of 5000
5000+10100×5000
=5500
It decreases by 20% in 2nd year.
Population at the end of 2nd year = Population at the starting of 3rd year,
5500-20% of 5500
5500-20100×5500
5500-1100
4400
It increases by 30% in 3rd year,
Population at the end of 3rd year =4400+30% of 4400
4400+30100×4400
4400+1320
5720
Therefore, the population of area at the end of 3 years is 5720.
Hence, the correct option is (3) .
 
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