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Q.

The population of a town increases by 10% annually. If the present population is 600000, what will be its population after 2 years?


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a

72600

b

7260

c

72

d

3454 

answer is A.

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Detailed Solution

Given, the population of a town increases by 10% annually.
Present population = 60000.
Increment per year = 10%.
Population after 1st year = 60000 + 10% of 60000.
We know that a% of b = a100×b where a and b are real numbers.
⇒ Population after 1st year = 60000+10100×60000
⇒ Population after 1st year = 60000+6000
⇒ Population after 1st year = 66000
Population after 2nd year = 66000 + 10% of 66000.
⇒ Population after 2nd year = 66000+10100×66000
⇒ Population after 2nd year = 66000+6600
⇒ Population after 2nd year = 72600
The population of the town after 2 years will be 72600.
Hence, option 1 is correct.
 
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The population of a town increases by 10% annually. If the present population is 600000, what will be its population after 2 years?