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Q.

The population of a town increases by 5% every year. lf the present population is 9261, the population 3 years ago was

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a

5700

b

6000

c

8000

d

7500

answer is D.

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Detailed Solution

Population 3 yrs. ago $= \frac{9261}{{(1 + \frac{5}{100})}^{3}}$

$= \frac{9261 \times 20 \times 20 \times 20}{21 \times 21 \times 21} = 8000$

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