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Q.

The position of a particle moving in the XY-plane at any time 't' is given by x=(3t2-6t)m; y=(t2-2t)m.Select the correct statement about the moving particle from the following

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a

The acceleration of the particle is zero at t=0 second

b

The velocity of the particle is zero at t=0 second

c

The velocity of the particle is zero at t=1 second

d

The velocity and acceleration of the particle are never zero

answer is C.

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Detailed Solution

Position of a particle moving in the XY plane be  t,

x = (3t2 - 6t)m

y= (t - 2t)m

Let, 

i^= x

j^ = y

Substituting the value we get , 

 a = d2xdt2 i^+d2ydt2 j^ 

a = 6 i^+ 2j^

v = dxdti^ + dvdtj^

v = (6t-6) i^+ (2t-2) j^

v(t=0) = -6 i^ - 2 j^

v(t=1) = 0 i^ + 0 j^ = 0

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