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The position-time graph of a body of mass $2 k g$ is as shown in figure. What is the impulse on the body at $t = 4 s$ ?

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$- \frac{3}{2} k g m s^{- 1}$

$- \frac{2}{3} k g m s^{- 1}$

$\frac{3}{2} k g m s^{- 1}$

$\frac{2}{3} k g m s^{- 1}$

answer is D.

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Detailed Solution

At $t = 4 s$ , the body has constant velocity $u = \frac{3}{4} m s^{- 1}$

After $t = 4 s$ , the body is at rest i.e. $ν = 0$

Impulse $= m (ν - u) = 2 k g (0 - \frac{3}{4} m s^{- 1}) = - \frac{3}{2} k g m s^{- 1}$

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