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The position vectors of $A$ and $B$ are $2 i - 9 j - 4 k$ and $6 i - 3 j + 8 k$ respectively, then the magnitude of $\vec{A B}$ is :

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answer is D.

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Detailed Solution

$\vec{A B} = (6 - 2) i + (- 3 + 9) j + (8 + 4) k = 4 i + 6 j + 12 k$

$| \bar{A B} | = \sqrt{16 + 36 + 144} = 14 .$

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