The position x of a particle at time t is given by x=V0a1−e−at, where V0 is constant and a > 0. The dimensions of V0 and a are

Here at is dimensionless. Soa=1t=1T=T−1x=V0a and V0=xa=LT−1=M0LT−1

The position x of a particle at time t is given by x=V0a1−e−at, where V0 is constant and a > 0. The dimensions of V0 and a are

Here at is dimensionless. Soa=1t=1T=T−1x=V0a and V0=xa=LT−1=M0LT−1

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The position x of a particle at time t is given by $x = \frac{V_{0}}{a} (1 - e^{- at})$ , where V₀ is constant and a > 0. The dimensions of V₀ and a are

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$M^{0} {LT}^{- 1} and T^{- 1}$

$M^{0} {LT}^{0} and T^{- 1}$

$M^{0} {LT}^{- 1} and {LT}^{- 2}$

$M^{0} {LT}^{- 1} and T$

answer is A.

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Here at is dimensionless. So

$\begin{matrix} a = \frac{1}{t} = [\frac{1}{T}] = [T^{- 1}] \\ x = \frac{V_{0}}{a} and V_{0} = xa = [{LT}^{- 1}] = [M^{0} {LT}^{- 1}] \end{matrix}$

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The position x of a particle at time t is given by x=V0a1−e−at, where V0 is constant and a > 0. The dimensions of V0 and a are

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The position x of a particle at time t is given by $x = \frac{V_{0}}{a} (1 - e^{- at})$ , where V₀ is constant and a > 0. The dimensions of V₀ and a are