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Q.

The position x of a particle varies with time t as x = at2 – bt3. The acceleration of the particle will be zero at time t equal to

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a

2a3b

b

ab

c

a3b

d

Zero

answer is C.

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Detailed Solution

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Position x = at2 - bt3

Velocity =dxdt=ddtat2bt3

Velocity = 2ta – 3bt2

Acceleration = dvdt=ddt2ta3bt2

Acceleration = 2a – 6bt = 0
=2a=6btt=a3b

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