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Q.

The position x of a particle varies with time t as x=at2−bt3. The acceleration of the particle will be zero at time t equal to

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a

2a3b

b

1b

c

c

d

a3b

answer is C.

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Detailed Solution

Given, x=at2−bt3

Velocity, v=dxdt=2at−3bt2

Acceleration, d2xdt2=2a−6bt

time when acceleration is zero,

2a−6bt=0⇒ t=a3b

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