The positive value of the standard electrode potential of Cu²⁺/Cu indicates that

Lesser the E^o value of redox couple, higher is the reducing power.
                $\begin{array}{r}{\mathrm{Cu}}^{2+}+2{\mathrm{e}}^{-}⟶\mathrm{Cu}{\mathrm{E}}^{\circ }=0.34\mathrm{V}\\ 2{\mathrm{H}}^{+}+2{\mathrm{e}}^{-}⟶{\mathrm{H}}_2{\mathrm{E}}^{\circ }=0.00\mathrm{V}\end{array}$
      Since, 2H⁺/ H₂ has lesser SRP than Cu²⁺ /Cu redox couple. Therefore,
(i) This redox couple is a stronger oxidising agent than H⁺/H_2.
(ii) Cu cannot displace H₂ from acids.