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The possible value of l and m for the last electron in the ${Cl}^{-}$ ion are

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1 and 2

2 and + 1

3 and -1

1 and -1

answer is D.

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Detailed Solution

${Cl}_{17}^{-} : [Ne] 3 s^{2} 3 p^{6} .$

Last electron enters 3p orbital.

$∴ l = 1 and m = 1, 0, - 1 .$

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