The potential at a point x (measured in µ m) due to some charges situated on the x-axis is given by V(x)=20x2−4volt. The electric fieldE at x = 4 m m is given by

10 9 V μm and in the negative x - direction

10 9 V μm and in the negative x - direction

10 9 V μm and in the positive x -direction

5 3 V μm and in the positive x - direction

10 9 V μm and in the negative x - direction

5 3 V μm and in the negative x -direction

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The potential at a point x (measured in µ m) due to some charges situated on the x-axis is given by $V (x) = \frac{20}{x^{2} - 4}$ volt. The electric field
E at x = 4 m m is given by

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$\frac{10}{9} \frac{V}{μm} and in the positive x -direction$

$\frac{5}{3} \frac{V}{μm} and in the positive x - direction$

$\frac{10}{9} \frac{V}{μm} and in the negative x - direction$

$\frac{5}{3} \frac{V}{μm} and in the negative x -direction$

answer is C.

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$E = - \frac{dv}{dx}$

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