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Q.

The potential at the origin is zero due to electric field $\vec{E} = 40 \vec{i} + 60 \vec{j} {NC}^{- 1}$ . The potential at point P (3m, 3m)

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a

–100 V

b

20 V

c

1 V

d

– 300 V

answer is B.

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Detailed Solution

$\begin{array}{l} dV = - \bar{E} \cdot \bar{dr} = - (40 i + 60 j) \cdot (3 i + 3 j) \\ = - [120 + 180] = - 300 V \end{array}$

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The potential at the origin is zero due to electric field E→=40i→+60j→NC−1 . The potential at point P (3m, 3m)