The potential at the origin is zero due to electric field E = 20i^ + 30j^ NC–1. The potential at point P(2m, 2m) is

V=−E→⋅dr¯=−(20i+30j)⋅(2i+2j)=−[40+60]=−100V

The potential at the origin is zero due to electric field E = 20i^ + 30j^ NC–1. The potential at point P(2m, 2m) is

V=−E→⋅dr¯=−(20i+30j)⋅(2i+2j)=−[40+60]=−100V

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The potential at the origin is zero due to electric field $E = 20 \hat{i} + 30 \hat{j}$ NC^–1. The potential at point P(2m, 2m) is

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1 V

–100 V

10 V

2 V

answer is B.

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Detailed Solution

$\begin{array}{l} V = - \vec{E} \cdot \bar{dr} = - (20 i + 30 j) \cdot (2 i + 2 j) \\ = - [40 + 60] = - 100 V \end{array}$

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The potential at the origin is zero due to electric field E = 20i^ + 30j^ NC–1. The potential at point P(2m, 2m) is

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The potential at the origin is zero due to electric field $E = 20 \hat{i} + 30 \hat{j}$ NC^–1. The potential at point P(2m, 2m) is