The potential difference between A and B is

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answer is C.

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Detailed Solution

$V_{A} - V_{B} = \frac{\frac{e_{1}}{r_{1}} + \frac{e_{2}}{r_{2}}}{\frac{1}{r_{1}} + \frac{1}{r_{2}}} = \frac{\frac{10}{2} + \frac{(- 2)}{1}}{\frac{1}{2} + \frac{1}{1}} volt$

$\Rightarrow V_{A} - V_{B} = \frac{5 - 2}{3 / 2} volt = 2 volt$

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