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Q.

The potential difference in open circuit for a cell is 2.2 volts. When a 4 ohm resistor is connected between its two electrodes the potential difference becomes 2 volts. The internal resistance of the cell will be

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a

0.4 ohm

b

1 ohm

c

0.2 ohm

d

2.5 ohm

answer is D.

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Detailed Solution

The potential difference in open circuit for the cell is 2.2 volts, it means the emf of the battery should be 2.2 volts.

Now a 4 ohm resistor is connected between its two electrodes, then the potential difference across the battery becomes 2 volts.

V=εir2=2.2ir    ir=0.2  V                                                         ....iBut  i=εr+R=2.2r+4                              .....ii

Putting the value of i in (i), we get r = 0.4 ohm.

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